How do you graph #x^2 + y^2 -6x + 2y - 6 = 0#?

1 Answer
Alan P.
Jan 26, 2016

Draw a circle with center #(3,-1)# and radius #4#.

Explanation:

#x^2+y^2-6x+2y-6=0#

#rarr color(red)(x^2-6x)+color(blue)(y^2+2y)=color(green)(6)#

#rarr color(red)(x^2-6x+9)+color(blue)(y^2+2y+1) = color(green)(6)color(red)(+9)color(blue)(+1)#

#rarr color(red)((x-3)^2) + color(blue)((y+1)^2) = color(orange)(4^2)#

which is the standard form for a circle with center #(3,-1)# and radius #4#.

graph{x^2-6x+y^2+2y-6=0 [-8.1, 9.68, -5.404, 3.48]}

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