How do you graph $x^2 + y^2 -6x + 2y - 6 = 0$ ?

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Answer 1 · 2016-01-26T11:50:00

Draw a circle with center $(3,-1)$ and radius $4$ .

$x^2+y^2-6x+2y-6=0$

$rarr color(red)(x^2-6x)+color(blue)(y^2+2y)=color(green)(6)$

$rarr color(red)(x^2-6x+9)+color(blue)(y^2+2y+1) = color(green)(6)color(red)(+9)color(blue)(+1)$

$rarr color(red)((x-3)^2) + color(blue)((y+1)^2) = color(orange)(4^2)$

which is the standard form for a circle with center $(3,-1)$ and radius $4$ .

graph{x^2-6x+y^2+2y-6=0 [-8.1, 9.68, -5.404, 3.48]}

How do you graph x^2 + y^2 -6x + 2y - 6 = 0x^2 + y^2 -6x + 2y - 6 = 0?