How do you graph using the intercepts for #x-4y=33#?

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Answer 1 · 2016-02-07T02:37:21

Refer Explanation section

Given -

#x-4y=33#

Y - intercept

At #x=0#

#0-4y=33#
#y=33/(-4)=-33/4=-8.25#

#(0, -8.25)#

X - Intercept

At #y=0#

#x-4(0)=33#
#x=33#

#(33, 0)#

Plot the points #(0, 8.25)# and #(33, 0)#

Join them with the help of a straight line.

Look at the diagram