How do you graph using the intercepts for $6 x - y = 4$ $6x - y = 4$ ?

Question

How do you graph using the intercepts for $6 x - y = 4$ $6x - y = 4$ ?

2 Answers

Impact of this question

3502 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-16T19:42:15

$y = 6 x - 4$ $y=6x-4$
$x_{1} = 1 \Rightarrow y_{1} = 6 \cdot 1 - 4 = 2$ $x_1=1rArry_1=6*1-4=2$
$x_{2} = 2 \Rightarrow y_{2} = 6 \cdot 2 - 4 = 8$ $x_2=2rArry_2=6*2-4=8$
graph{y=6x-4 [-10, 10, -5, 5]}

Answer 2 · 2018-05-16T19:45:21

$see explanation$ $"see explanation"$

Explanation:

$to find the intercepts, that is where the graph crosses$ $"to find the intercepts, that is where the graph crosses"$
$the x and y axes$ $"the x and y axes"$

$∙ let x = 0, in the equation for y-intercept$ $• " let x = 0, in the equation for y-intercept"$

$∙ let y =0, in the equation for x-intercept$ $• " let y =0, in the equation for x-intercept"$

$x = 0 \Rightarrow 0 - y = 4 \Rightarrow y = - 4 \leftarrow y-intercept$ $x=0rArr0-y=4rArry=-4larrcolor(red)"y-intercept"$

$y = 0 \Rightarrow 6 x - 0 = 4 \Rightarrow x = \frac{4}{6} = \frac{2}{3} \leftarrow x-intercept$ $y=0rArr6x-0=4rArrx=4/6=2/3larrcolor(red)"x-intercept"$

$plot the points (0, - 4) and (\frac{2}{3}, 0)$ $"plot the points "(0,-4)" and "(2/3,0)$

$and draw a straight line through them for graph$ $"and draw a straight line through them for graph"$
graph{(y-6x+4)((x-0)^2+(y+4)^2-0.04)((x-2/3)^2+(y-0)^2-0.04)=0 [-14.24, 14.23, -7.12, 7.12]}

Science

Math

Humanities

... and beyond

How do you graph using the intercepts for $6 x - y = 4$ $6x - y = 4$ ?

2 Answers

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you graph using the intercepts for 6x−y=46x - y = 4 ?

2 Answers

Explanation:

Related questions

Impact of this question

How do you graph using the intercepts for $6 x - y = 4$ $6x - y = 4$ ?