How do you graph #theta = -pi/4#? Trigonometry The Polar System Graphing Basic Polar Equations 1 Answer A. S. Adikesavan Mar 27, 2016 #theta#=-pi/4 is the radial line bisecting the fourth quadrant. Explanation: Rotate the initial line #theta# = 0 in the clockwise sense to the position #theta=-pi/4#. Answer link Related questions What are limacons and cardioids? How do you graph basic polar equations? How do you determine the shape of a limaçon from the polar equation? How do you graph #r = 1.5#? How do you graph #\theta = 30^\circ#? What does the graph of #r = \cos \theta# such that #0^\circ \le \theta \le 360^\circ# look like? What is the general form of limacons and cardioids and how do you graph transformations? How do you graph the equation #r = 1 + cos( theta )#? How do you graph #r=3-2costheta#? How do you graph #r=1-cosx#? See all questions in Graphing Basic Polar Equations Impact of this question 3818 views around the world You can reuse this answer Creative Commons License