How do you graph the parabola #y= - 1/2 * x^2# using vertex, intercepts and additional points?
1 Answer
Feb 14, 2018
Look at the explanation section.
Explanation:
Given -
#y=-1/2x^2#
Since it has no constant term, Its vertex and intercept is
Take a few points on either side of
Tabulate the va;ues.
Plot the pair of points.
Join all the points.
You get the parabola.
