How do you graph the line #y = 2/3x + 4#?

1 Answer
David Drayer · EZ as pi
Sep 6, 2016
  • Start at the point # (0,4)# then go up two and three to the right.
    Repeat and connect the points with a straight line.

Explanation:

Use the y = mx + b form. b is the y intercept - the place where the line crosses the y-axis. ( b = beginning)

The y intercept is the point where #x = 0#

In this equation #b = 4#. This is the y intercept where #x = 0#

So the point to start graphing from is #(0, 4)#
The x-value is always first in a point #(x, y) #

The slope is the angle at which the line leans.

This is the #m# in the the #y = mx + b# equation.
(m = mountain slope)

In this equation, # m = 2/3#

Slope equals # (Deltay)/(Deltax) # so #y =2 and x = 3.#

#y# is the up and down value so the line moves up 2 points.
( 2 is positive so the line goes up 2: if the value was -2 the line would go down 2)

#x# is the right and left value so the line moves three points to the right.
(3 is positive so the line goes to the right:
If the value was negative the line would go to the left.)

Count 2 up and three to the right and make a point,
Do this procedures several times starting at #(0,4)#
The points will connect in a straight line.

Related questions
See all questions in Graphs of Linear Equations
Impact of this question
6226 views around the world
You can reuse this answer
Creative Commons License