How do you graph the function #y=f(x)=x^2+1#?

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Answer 1 · 2018-07-02T05:30:19

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Given: #f(x) = x^2 + 1#

You can use point plotting. Select any #x# value and then calculate the #y# value and plot.

#ul(" "x" "| " "y" ")#
#""-4" "|" "17#
#""-2" "|" "5#
#" "0" "|" "1#
#" "2" "|" "5#
#" "4" "|" "17#

or you can realize that #x^2 + 1# is a vertical shift up #1# of the parent function #f(x) = x^2#

or you can just graph the function using a graphing calculator.

TI-83, 84: Y= X^2 + 1 then select GRAPH

graph{x^2+1 [-5, 5, -4, 20]}