How do you graph the function f(x) = -1/3 (x-2)^2 +3?

1 Answer
Bill K.
Sep 3, 2015

Its graph is a parabola opening downward with vertex (x,y)=(2,3), y-intercept y=5/3, and x-intercepts at x=-1,5. You can also plot more points to help you draw the graph.

Explanation:

A quadratic function f(x)=a(x-h)^2+k is said to be in vertex form and has vertex (high or low point) at the point (x,y)=(h,k). This will be a low point if a>0 (the parabola opens upward) and a high point if a<0 (the parabola opens downward).

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