How do you graph the equation by plotting points $y = x - 2$ $y = x - 2$ ?

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How do you graph the equation by plotting points $y = x - 2$ $y = x - 2$ ?

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Answer 1 · 2018-06-13T07:31:37

See below

Explanation:

This is the equation of a line, so you only need two points to plot it. To find two points on the line, plug two random $x$ $x$ values and compute the corresponding $y$ $y$ values. For example, let's choose $x = 0$ $x=0$ and $x = 1$ $x=1$ .

$x = 0$ $x = 0$ yields $y = 0 - 2 = - 2$ $y = 0 - 2 = -2$

So, the first point is $(0, - 2)$ $(0,-2)$

$x = 1$ $x = 1$ yields $y = 1 - 2 = - 1$ $y = 1 - 2 = -1$

So, the first point is $(1, - 1)$ $(1,-1)$

Draw the two points and connect them, and you have the line

Answer 2 · 2018-06-13T07:36:32

$see explanation$ $"see explanation"$

Explanation:

$one way is to find the intercepts, that is where the graph$ $"one way is to find the intercepts, that is where the graph"$
$crosses the x and y axes$ $"crosses the x and y axes"$

$∙ let x = 0, in the equation for y-intercept$ $• " let x = 0, in the equation for y-intercept"$

$∙ let y = 0, in the equation for x-intercept$ $• " let y = 0, in the equation for x-intercept"$

$x = 0 \Rightarrow y = - 2 \leftarrow y-intercept$ $x=0rArry=-2larrcolor(red)"y-intercept"$

$y = 0 \Rightarrow x - 2 = 0 \Rightarrow x = 2 \leftarrow x-intercept$ $y=0rArrx-2=0rArrx=2larrcolor(red)"x-intercept"$

$plot the points (0, - 2) and (2, 0)$ $"plot the points "(0,-2)" and "(2,0)$

$draw a straight line through them for graph$ $"draw a straight line through them for graph"$
graph{(y-x+2)((x-0)^2+(y+2)^2-0.04)((x-2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

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How do you graph the equation by plotting points $y = x - 2$ $y = x - 2$ ?

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How do you graph the equation by plotting points y = x - 2y=x−2y = x - 2?

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How do you graph the equation by plotting points $y = x - 2$ $y = x - 2$ ?