How do you graph the equation by plotting points $y = -3x + 2$ ?

Question

2404 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-06T11:16:23

See a solution process below:

First, we can find two points to plot.

For $x = 0:$

$y = (-3 * 0) + 2$

$y = 0 + 2$

$y = 2$ or $(0, 2)$

For $x = 2:$

$y = (-3 * 2) + 2$

$y = -6 + 2$

$y = -4$ or $(2, -4)$

We can then plot these two points:

graph{(x^2+(y-2)^2-0.125)((x-2)^2+(y+4)^2-0.125)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points:

graph{(y+3x-2)(x^2+(y-2)^2-0.125)((x-2)^2+(y+4)^2-0.125)=0 [-15, 15, -7.5, 7.5]}

How do you graph the equation by plotting points y = -3x + 2y = -3x + 2?