How do you graph the equation by plotting points #y = -3x + 2#?

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Answer 1 · 2017-08-06T11:16:23

See a solution process below:

First, we can find two points to plot.

For #x = 0:#

#y = (-3 * 0) + 2#

#y = 0 + 2#

#y = 2# or #(0, 2)#

For #x = 2:#

#y = (-3 * 2) + 2#

#y = -6 + 2#

#y = -4# or #(2, -4)#

We can then plot these two points:

graph{(x^2+(y-2)^2-0.125)((x-2)^2+(y+4)^2-0.125)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points:

graph{(y+3x-2)(x^2+(y-2)^2-0.125)((x-2)^2+(y+4)^2-0.125)=0 [-15, 15, -7.5, 7.5]}