How do you graph the equation by plotting points, y=1/5x-3?

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Answer 1 · 2017-08-17T02:34:15

See a solution process below:

First, we can determine two points on the line by solving the equation for two different values of $x$ $x$ :

For $x = 0$ $x = 0$ : $y = (\frac{1}{5} \times 0) - 3)$ $y = (1/5 xx 0) - 3)$

$y = 0 - 3$ $y = 0 - 3$

$y = - 3$ $y = -3$ or $(0, - 3)$ $(0, -3)$

For $x = 5$ $x = 5$ : $y = (\frac{1}{5} \times 5) - 3)$ $y = (1/5 xx 5) - 3)$

$y = 1 - 3)$ $y = 1 - 3)$

$y = - 2$ $y = -2$ or $(5, - 2)$ $(5, -2)$

We can plot these two points on the grid as:

graph{(x^2+(y+3)^2-0.05)((x-5)^2+(y+2)^2-0.05)=0 [-20,20,-10,10]}

Now, draw a straight line through the two points to graph the equation:

graph{(x^2+(y+3)^2-0.05)((x-5)^2+(y+2)^2-0.05)(y-1/5x+3)=0 [-20,20,-10,10]}