How do you graph the equation by plotting points $f(x) = –16x^2 + 8x + 3$ ?

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Answer 1 · 2018-06-12T13:37:02

$(-b)/(2a)$ gives the axis of symmetry

$-8/-32=1/4$

$x=1/4$ is the axis of symmetry

It is $nn$ shaped as it is a negative $x^2$ with a maximum at $(1/4,4)$

Put $x=-1, 0, 1/4,1$ into the equation to get the corresponding $y$ values

How do you graph the equation by plotting points f(x) = –16x^2 + 8x + 3f(x) = –16x^2 + 8x + 3?