How do you graph the equation by plotting points $3x - 2y =4$ ?

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Answer 1 · 2016-05-07T03:59:50

Function: $y=-2+3/2x$
Intercepts: ( $0, -2$ ) and ( $4/3, 0$ ). The graph is a line that passes through these points.

First of all, you must make a function out of this equation. A function is defined as $y=f(x)$ , so you can start by isolating $y$ :

$-2y=4-3x$
$y=(4-3x)/-2 = -2+3/2x$

Next, since this is a linear function, you can find the intercepts of the function.
With $x=0$ :
$y=-2+cancel(3/2*(0))=-2$

And with $y=0$ :
$0=-2+3/2x$
$3x/2=2$
$3x=4$
$x=4/3$

We now have the points ( $0, -2$ ) and ( $4/3, 0$ ). We can just make a line that passes through them in the graph:

graph{3/2x-2 [-5, 5, -5, 5]}

How do you graph the equation by plotting points 3x - 2y =43x - 2y =4?