How do you graph the equation by plotting points $3 x - 2 y = 15$ $3x-2y=15$ ?

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Answer 1 · 2017-10-27T13:34:16

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 1$ $x = 1$

$(3 \cdot 1) - 2 y = 15$ $(3 * 1) - 2y = 15$

$3 - 2 y = 15$ $3 - 2y = 15$

$- 3 + 3 - 2 y = - 3 + 15$ $-3 + 3 - 2y = -3 + 15$

$0 - 2 y = 12$ $0 - 2y = 12$

$- 2 y = 12$ $-2y = 12$

$\frac{- 2 y}{- 2} = \frac{12}{- 2}$ $(-2y)/-2 = 12/-2$

$y = - 6$ $y = -6$ or $(1, - 6)$ $(1, -6)$

Second Point: For $y = 0$ $y = 0$

$3 x - (2 \cdot 0) = 15$ $3x - (2 * 0) = 15$

$3 x - 0 = 15$ $3x - 0 = 15$

$3 x = 15$ $3x = 15$

$\frac{3 x}{3} = \frac{15}{3}$ $(3x)/color(red)(3) = 15/color(red)(3)$

$x = 3$ $x = 3$ or $(5, 0)$ $(5, 0)$

We can next plot the two points on the coordinate plane:

graph{((x-1)^2+(y+6)^2-0.075)((x-5)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x-2y-15)((x-1)^2+(y+6)^2-0.075)((x-5)^2+y^2-0.075)=0 [-20, 20, -10, 10]}

How do you graph the equation by plotting points 3x−2y=153x-2y=15?