How do you graph #r=8cos(theta)-2sin(theta)#?

1 Answer
A. S. Adikesavan
Jul 27, 2018

See graph and explanation.

Explanation:

Convert #r = 8 cos theta - 2 sin theta# to Cartesian form

#x^2 + y^2 - 8 x +2 y = 0, using

#r = sqrt( x^2 + y^2 ) >= 0 and ( x, y ) = r ( cos theta, sin theta )#.

The Socratic graph of this circle,

with center at #( 4, - 1 )# and radius #sqrt(17)#.

is immediate.
graph{(x^2+y^2-8x+2y)((x-4)^2+(y+1)^2-0.04)=0[-1 23 -6 6] }

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