How do you graph r=8+6cosθ?

1 Answer
A. S. Adikesavan
Jan 5, 2017

Using Socratic graphic utility, the graph of the limacon could be inserted, for the cartesian form x2+y2=8√x2+y2+6x.

Explanation:

r=8+6cosθ≥2.

Asr(θ)=r(−θ), the graph is symmetrical about θ=0.

Range of r is from 2 to 14. 1-period ( θ∈[−π.π]) is inserted.

graph{x^2+y^2-6x-8sqrt(x^2+y^2)=0x^2 [-24, 24, -12, 12]}

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