How do you graph #r= 4cosθ#?

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Answer 1 · 2016-03-29T23:20:14

the graph of #r=4 cos theta# is a Circle

You can also try converting #r=4 cos theta# to rectangular coordinates system

#r=4 cos theta#

#sqrt(x^2+y^2)=4* x/sqrt(x^2+y^2)#

#x^2+y^2-4x=0#

#x^2+y^2-4x+4=4#

#(x-0)^2+(y-2)^2=4#

#(x-0)^2+(y-2)^2=2^2" "#a circle with radius of #r=2# and center at #(0, 2)#

Kindly see the graph

![www.desmos.com]( useruploads.socratic.org )

God bless....I hope the explanation is useful.