How do you graph r = 3sin ((theta) + pi/4)r=3sin((θ)+π4)?

1 Answer
Mar 9, 2016

Draw circle with center at (3/2, 3pi/4)(32,3π4) and radius 3/232.

Explanation:

The general equation of a circle with center at (d/2, pi/2+alpha) and radius=d/2(d2,π2+α)andradius=d2 is
r=d sin (theta+alpha)r=dsin(θ+α).

Here, d =3 and alpha=pi/4α=π4. The circle passes through r = 0. d is diameter of the circle.

Make a table (r, theta)}, theta=0,pi/4,pi/2,3pi/4,pi,5pi/4,3pi/2,5pi/4 and 2pi(r,θ)},θ=0,π4,π2,3π4,π,5π4,3π2,5π4and2π, and mark the points on the circle.