How do you graph #r = 3sin ((theta) + pi/4)#?

1 Answer
A. S. Adikesavan
Mar 9, 2016

Draw circle with center at #(3/2, 3pi/4)# and radius #3/2#.

Explanation:

The general equation of a circle with center at #(d/2, pi/2+alpha) and radius=d/2# is
#r=d sin (theta+alpha)#.

Here, d =3 and #alpha=pi/4#. The circle passes through r = 0. d is diameter of the circle.

Make a table #(r, theta)}, theta=0,pi/4,pi/2,3pi/4,pi,5pi/4,3pi/2,5pi/4 and 2pi#, and mark the points on the circle.

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