How do you graph #r = 3 sec (theta + 90°)#?

1 Answer
A. S. Adikesavan
Oct 16, 2016

Draw the straight line parallel to the compounded initial line #theta= 0 and theta = pi#, at a distance 3. in the direction #theta = 3/2pi#.

Explanation:

This is the polar form for# y = -3#

Here, #r = 3sec(theta+ 90^o)=3(-csc theta)=-3/sin theta#

So, y = r sin theta = -3

Draw the straight line parallel to the compounded initial line #theta= 0 and theta = pi#, at a distance 3. in the

direction #theta = 3/2pi#.

Related questions
See all questions in Graphing Basic Polar Equations
Impact of this question
1658 views around the world
You can reuse this answer
Creative Commons License