How do you graph f(x)=(1/2)^x -3 by plotting points?

1 Answer
flamespirit919
Apr 27, 2017

Pick values for x that are easy to solve

Explanation:

So we can choose the following x values:
x=-3,-2,-1,0,1,2

Plugging in the values we get the following
f(-3)=\frac{2^3}{1^3}-3=2^3-3=8-3=5
f(-2)=\frac{2^2}{1^2}-3=2^2-3=4-3=1
f(-1)=\frac{2^1}{1^1}-3=2^1-3=2-3=-1
f(0)=\frac{1^0}{2^0}-3=1-3=-2
f(1)=\frac{1^1}{2^1}-3=\frac{1}{2}-3=-\frac{5}{2}
f(2)=\frac{1^2}{2^2}-3=\frac{1}{4}-3=-\frac{11}{4}

You can plug in the points (-3,5),(-2,1),(-1,-1),(0,-2),(1,-2.5),(2,-2.75) to get
graph{(1/2)^x-3 [-14.85, 10.46, -3.99, 8.67]}

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