How do you graph and state the max/min for # f(x) = -2x^2 + 9#?

1 Answer
Mark D.
May 18, 2018

To find the max/min use #(-b)/(2a)#

#=> 0/-4=0#

The quadratic is negative so it is #nn# shaped so it will have a maximum. It crosses the #y# axis at 9 so the max is (0,9)

Put the values x=-3, -2, -1, 1, 2, 3 into the equation to obtain the corresponding y values and plot them accordingly.

You should have a #nn# shaped parabola symmetrically drawn across the y axis with a max point at (0,9).

Related questions
See all questions in Quadratic Functions and Their Graphs
Impact of this question
1235 views around the world
You can reuse this answer
Creative Commons License