How do you graph #6x+4y=12# using intercepts?

1 Answer
Tony B
Mar 22, 2017

See explanation

Explanation:

Given:#" "6x+4y=12#

Believe it or not, if you divide both sides by 2 and plot you will find that both equations produce exactly the same plot.

Divide both sides by 2

#3x+2y=6#

You could manipulate this into the form #y=mx+c# but you do not need to.
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We know that the x-axis crosses the y-axis at #x=0# so to determine the y-intercept set #x=0#

#3x+2y=6" "->" "3(0)+2y=6#
#" "2y=6#
#" "y=3#

#y_("intercept")=3#
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We know that the y-axis crosses the x-axis at #y=0# so to determine the x-intercept set #y=0#

#3x+2y=6" "->" "3x+2(0)=6#
#" "3x=6#
#" "x=2#

#x_("intercept")=2#
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Mark your points and draw a straight line through them.

Tony B

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