How do you graph $4x+y=-8$ using intercepts?

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Answer 1 · 2017-05-14T22:23:31

$y$ -intercept at $(0, -8)$ .

$y = -4x -8$

The $y$ -intercept of a straight line $y=mx+c$ is given by $c$ .

Here $c = -8$ . so the graph intersects at $(0, -8)$ with a gradient $m$ , in this case $-4$ .

graph{y = -4x-8 [-10, 10, -5, 5]}

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