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How do you graph #4x+y=-8# using intercepts?

1 Answer

Zain B. · Stefan V.

May 14, 2017

#y#-intercept at #(0, -8)#.

Explanation:

#y = -4x -8#

The #y#-intercept of a straight line #y=mx+c# is given by #c#.

Here #c = -8#. so the graph intersects at #(0, -8)# with a gradient #m#, in this case #-4#.

graph{y = -4x-8 [-10, 10, -5, 5]}

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