How do you graph 4x-3y=12 using intercepts?
1 Answer
Aug 18, 2017
Explanation:
"find the intercepts as follows"
• " let x = 0, in the equation for y-intercept"
• " let y = 0, in the equation for x-intercept"
x=0to0-3y=12rArry=-4larrcolor(red)" y-intercept"
y=0to4x-0=12rArrx=3larrcolor(red)" x-intercept"
"plot the points "(0,-4),(3,0)"
"and draw a straight line through them for graph"
graph{4/3x-4 [-10, 10, -5, 5]}