How do you graph (4, -1/2), (1/5, 5) on the coordinate plane?

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How do you graph (4, -1/2), (1/5, 5) on the coordinate plane?

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Answer 1 · 2017-11-22T02:50:51

See a solution process below:

Explanation:

To plot the point $(4, - \frac{1}{2})$ $(4, -1/2)$ we need to go 5 units to the right on the $x$ $x$ axis and then $\frac{1}{2}$ $1/2$ unit down on the $y$ $y$ axis giving:

graph{((x - 4)^2 + (y + 0.5)^2 - 0.05) = 0 [-5, 15, -2, 8]}

To plot the point $(\frac{1}{5}, 5)$ $(1/5, 5)$ we need to go 1/5 of a unit to the right on the $x$ $x$ axis and then $5$ $5$ units up on the $y$ $y$ axis giving:

graph{((x - 0.2)^2 + (y - 5)^2 - 0.05 )((x - 4)^2 + (y + 0.5)^2 - 0.05) = 0 [-5, 15, -2, 8]}

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How do you graph (4, -1/2), (1/5, 5) on the coordinate plane?

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