How do you graph $3x - y =1$ ?

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Answer 1 · 2018-07-01T18:16:13

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$

$(3 * 0) - y = 1$

$0 - y = 1$

$-y = 1$

$color(red)(-1) xx -y = color(red)(-1) xx 1$

$y = -1$ or $(0, -1)$

Second Point: For $y = 2$

$3x - 2 = 1$

$3x - 2 + color(red)(2) = 1 + color(red)(2)$

$3x - 0 = 3$

$3x = 3$

$(3x)/color(red)(3) = 3/color(red)(3)$

$x = 1$ or $(1, 2)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+1)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(3x - y - 1)(x^2+(y+1)^2-0.04)((x-1)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

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