How do you graph 2x+y-4=0 by plotting points?

1 Answer
Jim G.
Jul 2, 2018

"see explanation"

Explanation:

"one way is to find the intercepts, that is where the graph"
"crosses the x and y axes"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

x=0rArry-4=0rArry=4larrcolor(red)"y-intercept"

y=0rArr2x-4=0rArrx=2larrcolor(red)"x-intercept"

"Plot the points "(0,4)" and "(2,0)

"Draw a straight line through them for graph"
graph{(y+2x-4)((x-0)^2+(y-4)^2-0.04)((x-2)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}

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