How do you graph 2x + 3y =-6 by plotting points?
1 Answer
Jun 15, 2018
Explanation:
"one way is to find the intercepts, that is where the graph"
"crosses the x and y axes"
• " let x = 0, in the equation for y-intercept"
• " let y = o, in the equation for x-intercept"
x=0rArr0+3y=-6rArry=-2larrcolor(red)"y-intercept"
y=0rArr2x+0=-6rArrx=-3larrcolor(red)"x-intercept"
"plot the points "(0,-2)" and "(-3,0)
"draw a straight line through them for graph"
graph{(y+2/3x+2)((x-0)^2+(y+2)^2-0.04)((x+3)^2+(y-0)^2-0.04)=0 [-10, 10, -5, 5]}
