How do you graph #2x+3y=12# using intercepts?
1 Answer
Dec 2, 2017
Explanation:
#"to find the intercepts that is where the graph crosses"#
#"the x and y axes"#
#• " let x = 0, in the equation for y-intercept"#
#• " let y = 0, in the equation for x-intercept"#
#x=0to0+3y=12rArry=4larrcolor(red)"y-intercept"#
#y=0to2x+0=12rArrx=6larrcolor(red)"x-intercept"#
graph{-2/3x+4 [-10, 10, -5, 5]}