How do you graph 2x+3y=12 using intercepts?

1 Answer
Jim G.
Dec 2, 2017

"see explanation"

Explanation:

"to find the intercepts that is where the graph crosses"
"the x and y axes"

• " let x = 0, in the equation for y-intercept"

• " let y = 0, in the equation for x-intercept"

x=0to0+3y=12rArry=4larrcolor(red)"y-intercept"

y=0to2x+0=12rArrx=6larrcolor(red)"x-intercept"
graph{-2/3x+4 [-10, 10, -5, 5]}

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