How do you graph -2x + 3y = 12 on a coordinate graph?

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How do you graph -2x + 3y = 12 on a coordinate graph?

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Answer 1 · 2015-08-15T06:03:33

Convert the equation to slope-intercept form. Use the equation to find two points. Plot the points and draw a straight line through the points.

Explanation:

$-2x+3y=12$ follows the standard form for a linear equation, $Ax+By=C$ .

In order to graph this equation, you need to convert it to the slope-intercept form, and solve fore $y$ . The slope-intercept form for a linear equation is $y=mx+b$ , where $m$ is the slope, and $b$ is the slope-intercept.

Convert the Standard Equation to Slope-intercept Form

$-2x+3y=12$

Add $2x$ to both sides of the equation.

$3y=2x+12$

Divide both sides by $3$ .

$y=2/3x+12/3$ =

$y=2/3x+4$

Now use the equation to find two points on the line. Plot them, then draw a straight line through the points.

Point A: $(0,4)$

If $x=0, y=4$

$y=2/3x+4$ =

Substitute $0$ for $x$ .

$y=2/3(0)+4$ =

$y=0+4=4$ =

$y=4$

Point B: $(-6,0)$

If $y=0, y=-6$

$y=2/3x+4$

Substitute $0$ for $y$ .

$0=2/3x+4$

Subtract $4$ from both sides.

$-4=2/3x$

Divide both sides by $2/3$ .

$-4/1-:2/3=x$ =

$-4/1xx3/2=x$ =

$-12/2=x$ =

$-6=x$

graph{y=2/3x+4 [-10, 10, -5, 5]}

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How do you graph -2x + 3y = 12 on a coordinate graph?

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