How do you graph $- 2 {tan}^{- 1} (\frac{x}{2})$ $-2 tan^(-1) (x/2)$ ?

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Answer 1 · 2018-07-27T04:57:18

$y = - 2 tan (\frac{x}{2}), \frac{x}{2} \neq (2 k + 1) \frac{π}{2}$ $y = - 2 tan ( x/2 ), x/2 ne ( 2 k + 1 ) pi/2$

$\Rightarrow$ $rArr$ asymptotic $x \neq (2 k + 1) π,$ $x ne ( 2 k + 1 ) pi,$

$k = 0, +-1, +-2, +-3, ...$

Period $= pi/(1/2) = 2pi$

See graph:
graph{(y+2 tan ( x/2 ))(x-pi +.01y)(x+pi +.01y)=0[-20 20 -10 10]}

How do you graph -2 tan^(-1) (x/2)−2tan−1(x2)-2 tan^(-1) (x/2)?