How do you graph $12(x+5)=(y-8)^2$ ?

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Answer 1 · 2018-02-01T00:40:30

Set it up in the form $y = f(x)$ , calculate some points, and plot it on graph paper.

$12(x + 5) = (y−8)^2$
$12x + 60 = y^2 -16y +64$
$x = (y^2 -16y + 64 - 60)/12$

$x = y^2/12 - 4/3y + 1/3$
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How do you graph 12(x+5)=(y-8)^2 12(x+5)=(y-8)^2?