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How do you FOIL #(x^2 + 7)(x^2 + 7)#?

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Jun 7, 2015

#(x^2+7)(x^2+7)# evaluated using FOIL

F irst terms: #x^2 xx x^2 = x^4#
O utside terms: #x^2 xx 7 = 7x^2#
I nside terms: #7 xx x^2 = 7x^2#
L ast terms: #7 xx 7 = 49#

Sum of FOIL #= x^4 + 14x^2 + 49#

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