Science

Math

Humanities

... and beyond

Socratic Meta
Featured Answers

Topics

How do you find zeros of #g(x)=12x^3-2x^2-2x#?

1 Answer

Nov 24, 2016

You can separate one #x# to reduce it to a second degree equation

Explanation:

#g(x)=12x^3−2x^2−2x = x*(12x^2−2x−2)#

so #g(x) = 0# when either #x = 0# or #12x^2−2x−2 = 0#.

Related questions

See all questions in Complex Conjugate Zeros

Impact of this question

1875 views around the world

You can reuse this answer
Creative Commons License