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How do you find zeros of #g(x)=12x^3-2x^2-2x#?

1 Answer

Nov 24, 2016

You can separate one #x# to reduce it to a second degree equation

Explanation:

#g(x)=12x^3−2x^2−2x = x*(12x^2−2x−2)#

so #g(x) = 0# when either #x = 0# or #12x^2−2x−2 = 0#.

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