How do you find two solutions of the equations $cottheta=-sqrt3$ ?

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How do you find two solutions of the equations $cottheta=-sqrt3$ ?

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Answer 1 · 2017-02-06T15:44:01

$(5pi)/6, (11pi)/6$

Explanation:

$cot t = 1/(tan t) = - sqrt3$ --> $tan t = - 1/sqrt3 = - sqrt3/3$ .
Use trig table of special arcs and unit circle:
$tan t = - sqrt3/3$ --> 2 solutions -->
$t = (5pi)/6$ , and $t = (5pi)/6 + pi = (11pi)/6$
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$(5pi)/6, (11pi)/6$

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How do you find two solutions of the equations $cottheta=-sqrt3$ ?

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How do you find two solutions of the equations $cottheta=-sqrt3$ ?