How do you find two solutions (in degree and radians) for $sec x= (-2sqrt3)/3$ ?

Question

1365 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-01T17:46:30

Solve $sec x = (-2sqrt3)/3$

Ans: $+- (5pi)/6$

$sec x = - (2sqrt3)/3 = - 2/sqrt3$ --> $cos x = - sqrt3/2$
Trig Table of Special Arc -->
$cos x = - sqrt3/2$ --> $x = +- (5pi)/6$ or $x = +- 150$ deg

How do you find two solutions (in degree and radians) for sec x= (-2sqrt3)/3sec x= (-2sqrt3)/3?