How do you find two solutions (in degree and radians) for $cot x = - 1$ $cotx = -1$ ?

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Answer 1 · 2015-10-02T13:27:40

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$cot x = - 1 \Rightarrow x = - \frac{π}{4} + k π$ $cotx=-1 => x=-pi/4+kpi$

$π ~ 180$ $pi~180$

$x = - 45 + k \cdot 180$ $x=-45 + k*180$

$k = 0$ $k=0$
$x_{1} = - \frac{π}{4}$ $x_1=-pi/4$
$x_{1} = - 45$ $x_1=-45$

$k = 1$ $k=1$
$x_{2} = - \frac{π}{4} + π = - \frac{π}{4} + \frac{4 π}{4} = \frac{3 π}{4}$ $x_2=-pi/4+pi=-pi/4+(4pi)/4=(3pi)/4$

$x_{2} = \frac{3 \cdot 180}{4} = 135$ $x_2=(3*180)/4=135$

How do you find two solutions (in degree and radians) for cotx = -1cotx=−1cotx = -1?