How do you find two solutions (in degree and radians) for $cot = -sqrt3$ ?

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Answer 1 · 2015-10-05T03:52:36

Solve $cot x = -sqrt3$ in degree and radians

Ans: $x = 150^@; 330^@$

Trig Table of Special Arcs gives __>
$cot x = -sqrt3$ --> arc $x = ((5pi)/6)$ and $x = ((11pi)/6)$
In Deg --> $x = 150^@$ and $x = 330^@$

How do you find two solutions (in degree and radians) for cot = -sqrt3cot = -sqrt3?