How do you find two quadratic function one that opens up and one that opens downward whose graphs have intercepts (0,0), (10,0)?
1 Answer
Jan 13, 2017
#f_"up"(x) = x^2-10x#
#f_"down"(x) = -x^2+10x#
Explanation:
Any quadratic function with these
#f(x) = ax(x-10) = ax^2-10ax" "# for some constant#a != 0#
It must take this form in order that
If
So we can use
#f_"up"(x) = x^2-10x#
#f_"down"(x) = -x^2+10x#
