How do you find two consecutive integers such that the sum of the first number and 3 times the second is 55?

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Answer 1 · 2016-10-26T19:26:44

The two consecutive integers are 13 and 14.

Let the first integer be #i#.

Then the second integer by definition would be #i + 1# because these are consecutive integers.

You problem can then be stated as:

#i + 3(i + 1) = 55#

Solving for #i# gives:

#i + 3I + 3 = 55#

#4i = 52#

#i = 13#

and therefore
#i + 1 = 14#

#3 * 14 = 42#

#42 + 13 = 55#