How do you find two consecutive even integers that have a sum of 450?

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Answer 1 · 2016-05-19T13:28:52

The two numbers are $224 and 226$ $224" and "226$

Let the first even number be $n$ $n$

Then the next number is $n + 1$ $n+1$ which is odd.
Then the number after that is $n + 2$ $n+2$ which is even.

So the two even number are $n and n + 2$ $n" and "n+2$

We are given that $n + n + 2 = 450$ $n+n+2=450$

Subtract 2 from both sides

$2 n = 448$ $2n=448$

Divide both sides by 2

$n = 224$ $n=224$

$\Rightarrow n + 2 = 226$ $=>n+2=226$

So $Left Hand side \to 224 + 226 \to 450$ $"Left Hand side "->224+226->450$

So LHS -> RHS thus the two numbers are $224 and 226$ $224" and "226$