How do you find the zeros, real and imaginary, of $y=-x^2+7x+12$ using the quadratic formula?

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Answer 1 · 2017-05-15T11:21:18

$x=7/2+sqrt97/2$
or
$x=7/2-sqrt97/2$

Let my awesome notebook explain :D
(I can't be bothered with all the symbols on Socratic so I'll just do it on paper and then take a photo)

The roots, or the zeros of this question is real because the discriminant is positive. The discriminant is the $sqrtb^2-4ac$ part.

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How do you find the zeros, real and imaginary, of y=-x^2+7x+12y=-x^2+7x+12 using the quadratic formula?