How do you find the zeros, real and imaginary, of $y= -x^2-5x+37$ using the quadratic formula?

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Answer 1 · 2016-02-29T17:04:42

$x = - 5/2 +- sqrt173/2$

$D = d^2 = b^2 - 4ac = 25 + 148 = 173$ --> $d = +- sqrt173$
$x = -b/(2a) +- d/(2a) = - 5/2 +- sqrt173/2$

How do you find the zeros, real and imaginary, of y= -x^2-5x+37 y= -x^2-5x+37 using the quadratic formula?