How do you find the zeros, real and imaginary, of $y=-x^2- 5x -35$ using the quadratic formula?

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Answer 1 · 2017-05-27T05:00:34

$-5/2 + i sqrt(115)/2 and -5/2 -i sqrt(115)/2$

For zeros, y=0, which makes it $x^2+5x+35=0$ . Solution using quadratic formula, is appended below#

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How do you find the zeros, real and imaginary, of y=-x^2- 5x -35y=-x^2- 5x -35 using the quadratic formula?