How do you find the zeros, real and imaginary, of $y=x^2/4+1/2x-5/4$ using the quadratic formula?

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Answer 1 · 2017-02-21T23:39:29

$x=-1+-2i$

$y=1/4x^2+1/2x-5/4$

$x=(-0.5+-sqrt(0.5^2-4(0.25)(1.25)))/(2(0.25)$

$x=(-0.5+-"i")/0.5=-1+-2i$

How do you find the zeros, real and imaginary, of y=x^2/4+1/2x-5/4 y=x^2/4+1/2x-5/4 using the quadratic formula?