How do you find the zeros, real and imaginary, of $y= -7x^2-5x+23$ using the quadratic formula?

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How do you find the zeros, real and imaginary, of $y= -7x^2-5x+23$ using the quadratic formula?

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Answer 1 · 2017-04-04T04:27:53

$x = (-5 +- 25.87)/14$

Explanation:

y = - 7x^2 - 5x + 23 = 0
Use the improved quadratic formula (Socratic Search).
D = d^2 = b^2 - 4ac = 25 + 644 = 669 --> d = +- 25.87
There are 2 real roots:
$x = - b/(2a) +- d/(2a) = - 5/14 +- (25.87)/14 = (-5 +- 25.87)/14$

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How do you find the zeros, real and imaginary, of $y= -7x^2-5x+23$ using the quadratic formula?

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How do you find the zeros, real and imaginary, of y= -7x^2-5x+23y= -7x^2-5x+23 using the quadratic formula?

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How do you find the zeros, real and imaginary, of $y= -7x^2-5x+23$ using the quadratic formula?