How do you find the zeros, real and imaginary, of $y= 7x^2+4x-24$ using the quadratic formula?

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Answer 1 · 2016-03-09T17:02:59

$x = - 4/14 +- 26.23/14$

y = 7x^2 + 4x - 24.
$D = d^2 = b^2 - 4ac = 16 + 672 = 688$ --> $d = +- 26.23$
There are 2 real roots:
$x = -b/(2a) +- d/(2a) = - 4/14 +- 26.23/14$

How do you find the zeros, real and imaginary, of y= 7x^2+4x-24y= 7x^2+4x-24 using the quadratic formula?