How do you find the zeros, real and imaginary, of $y=- 5x^2-22x+10$ using the quadratic formula?

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How do you find the zeros, real and imaginary, of $y=- 5x^2-22x+10$ using the quadratic formula?

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Answer 1 · 2016-05-20T03:55:08

$(11 +- 3sqrt19)/5$

Explanation:

Use the improved quadratic formula (Socratic Search)
$y = -5x^2 - 22x + 10 = 0$
$D = d^2 = b^2 - 4ac = 484 + 200 = 684 = 36(19)$
$d = +- 6sqrt19$
There are 2 real roots:
$x = -b/(2a) +- d/(2a) = 22/10 +- (6sqrt19)/-10 = (11 +- 3sqrt19)/5$

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How do you find the zeros, real and imaginary, of $y=- 5x^2-22x+10$ using the quadratic formula?

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Humanities

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How do you find the zeros, real and imaginary, of y=- 5x^2-22x+10 y=- 5x^2-22x+10 using the quadratic formula?

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Explanation:

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How do you find the zeros, real and imaginary, of $y=- 5x^2-22x+10$ using the quadratic formula?