How do you find the zeros, real and imaginary, of $y= 3x^2-43x-33$ using the quadratic formula?

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Answer 1 · 2018-06-09T09:32:50

$color(indigo)(x = (43 + sqrt2245)/6, (43-sqrt2245)/6$

$y = 3x^2 - 43x - 33$

$a = 3, b = -43, c = -33$

$"Quadratic formula is " x = (-b +- sqrt(b^2 - 4ac)) / (2a)$

$x = (43 +- sqrt(43^2 + (4 * 3 * 33))) / 6$

$color(indigo)(x = (43 + sqrt2245)/6, (43-sqrt2245)/6$

How do you find the zeros, real and imaginary, of y= 3x^2-43x-33y= 3x^2-43x-33 using the quadratic formula?