How do you find the zeros, real and imaginary, of =5(x-3)^2+3 using the quadratic formula?

1 Answer
bp
Jan 10, 2016

x=3+-isqrt(3/5)

Explanation:

For using quadratic formula, the given expression has to be put in quadratic form , that is 5x^2 -30x +48=0. Comparing with the quadratic formula a= 5, b= -30 and c= 48. Expression b^2-4ac<0 hence the equation would have imaginary roots. The roots would be x=3+-isqrt(3/5)

Related questions
See all questions in Quadratic Formula
Impact of this question
1311 views around the world
You can reuse this answer
Creative Commons License